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Python: Default Arguments

Let's look at the round() function, which rounds the number passed to it:

result = round(10.25, 0)  # 10.0

We passed two parameters to it:

  • Number to be rounded
  • Rounding accuracy

0 means that the rounding will be to an integer value. More often than not, you need to round to a whole number, not to two, three, four etc. decimal places. So the creators of the round function made the second parameter unnecessary and gave it a default value of 0 inside the function. So, you can choose to not specify the second parameter and the result will be the same:

result = round(10.25)  # 10.0

And if you need a different precision, you can pass a parameter:

# rounding to one decimal place
result = round(10.25, 1)  # 10.2

If a function in Python accepts optional arguments, they always come after the mandatory ones. There can be any number of them. It depends on the function itself, but they always go next to and at the end of the list of arguments.

Instructions

Round up the number written in the number variable to two decimal places and print the result on the screen.

The exercise doesn't pass checking. What to do? 😶

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In my environment the code works, but not here 🤨

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My code is different from the teacher's one 🤔

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Definitions

  • Default setting optional function parameter


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