Expressions like index = index + 1
occur quite often in JavaScript, so the creators of the language added a shortcut: index += 1
. This shortcut is usually referred to as syntactic sugar because it simplifies and "sweetens" the process of coding :)
There are shortcuts for all arithmetic operations and for string concatenation:
a = a + 1
→ a += 1
a = a - 1
→ a -= 1
a = a * 2
→ a *= 2
a = a / 1
→ a /= 1
a = a + 'foo'
→ a += 'foo'
Write the filterString()
function that takes a string and a character as input and returns a new string, from which all occurrences of the character are removed.
const str = 'If I look back I am lost';
filterString(str, 'I'); // 'f look back am lost'
filterString('zz Zorro', 'z'); // ' Zorro'
If you've reached a deadlock it's time to ask your question in the «Discussions». How ask a question correctly:
Tests are designed so that they test the solution in different ways and against different data. Often the solution works with one kind of input data but doesn't work with others. Check the «Tests» tab to figure this out, you can find hints at the error output.
It's fine. 🙆 One task in programming can be solved in many different ways. If your code passed all tests, it complies with the task conditions.
In some rare cases, the solution may be adjusted to the tests, but this can be seen immediately.
It's hard to make educational materials that will suit everyone. We do our best but there is always something to improve. If you see a material that is not clear to you, describe the problem in “Discussions”. It will be great if you'll write unclear points in the question form. Usually, we need a few days for corrections.
By the way, you can participate in courses improvement. There is a link below to the lessons course code which you can edit right in your browser.
Your exercise will be checked with these tests:
1import { test, expect } from '@jest/globals';
2import f from './index.js';
3
4test('test', () => {
5 const text = 'If I look back I am lost';
6 expect(f(text, 'I')).toEqual('f look back am lost');
7 expect(f('zz Zorro', 'z')).toEqual(' Zorro');
8});
9
Teacher's solution will be available in: